Addition of 6q + 1 and q + 11 is 7q + 12
<em><u>Solution:</u></em>
Given that, we have to add the given two expressions
<em><u>Given expressions are:</u></em>
6q + 1 and q + 11
We have to add both the expressions
Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11
Add the coefficients of same variable. Here "q" is present in two terms
Therefore, add 6q and q
Similarly, add the constants 1 and 11
<em><u>Thus finally addition is done as:</u></em>

Thus addition of 6q + 1 and q + 11 is 7q + 12
Answer:

Step-by-step explanation:
On a coordinate plane, a solid straight line has a positive slope and goes through (negative 4, 0) and (0, 2). This line has the equation

The origin belongs to the shaded region, so its coordinates must satisfy the inequality. Since

then the correct inequality is

A number 4 times as much as 25 is 100
Answer:
35 square units
Step-by-step explanation:
Area of the parallelogram = 7*5 = 35 square units