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3 years ago

If f(x) = x + 7 and g(x)=1/x, what is (f o g)(x)?

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

8 0

Answer: 1/x + 7

Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)

G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7

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What is the order magnitude for the number of days in a year ?

Scrat [10]

answer is 2: 1 x 10^2 –days.

I hope this helps!

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2 years ago

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Need help ASAP

iragen [17]

Answer:

Step-by-step explanation:

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2 years ago

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 m

bezimeni [28]

Answer: 0.75

Step-by-step explanation:

Given : Interval for uniform distribution : [0 minute, 5 minutes]

The probability density function will be :-

$f(x)=\dfrac{1}{5-0}=\dfrac{1}{5}=0.2\ \ ,\ 0$

The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-

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7 0

3 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the instanteous rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at exactly t=5, the rate of growth is 51.72 cells per hour.

And we're done!

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2 years ago

The box plots represent the ages of pennies in two 50-cent rolls. By looking at the plots, Beth says that the two means are abou

Neporo4naja [7]

Answer:

D)She may not be correct because means cannot be determined from Box plots.

Step-by-step explanation:

Box plot -Boxplot is a way to show the spread and centers of a data setboxplot and also called a box and whisker plot,

Box plot tells us about :

1) Mininmum value

2) 25th Percentile value

3)Median

4) 75th Percentile value

5)Maximum value

6) Interquartile Range

Now we are given that By looking at the plots, Beth says that the two means are about 5 years apart.

So,Option D is true

She may not be correct because means cannot be determined from Box plots.

6 0

2 years ago

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