70 ft per sec going upward 3 sec from 6 ft high should reach 216 ft, but unfortunately gravity is pulling it and at some point it starts to go backward (at 2.176 second), so to compensate the upward slowing down and distance dropped, use -32.176 times 3 square times 1/2 = -144.792 which is the natural drop distance if the football is released mid air without a initial speed after 3 seconds. 216 - 144.792 = 71.208 ft high.
Answer:
40078-18537=21541
Step-by-step explanation:
More than 3,529.41176 which rounds up to 3,500.
Divide both sides by 2 for the first one.
2c/2>2/2
c>1
simplify both sides for the second 1
1/6d>=1
6*(1/6d).=(6)*(1)
d>=6
For the last one
subtract 9 from both sides
r+9-9<=23-9 so that r<=14
Hope this helps!
