Question

Side MN = 6, side OM = 9, side PQ = 6, and side RP = 9. What side corresponds to side NO and can be used to show that ΔMNO ≅ ΔPQR by SSS? (Enter your answer using letters only)

Answer 1

I think the answer would be QR

Answer 2

Answer:

QR is the side corresponds to side NO.

Step-by-step explanation:

SSS(Side-Side-Side) Postulates states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

Given: Side MN= 6 units , OM = 9 units , PQ = 6 units and RP = 9.

In triangle MNO and triangle PQR

MN = PQ = 6 units            [Side]

OM = RP = 9 units.           [Side]

NO = QR                           [Side]

Then; by SSS postulates

$\triangle MNO \cong \triangle PQR$

Therefore, the sides which corresponds to side NO is, QR .