Side MN = 6, side OM = 9, side PQ = 6, and side RP = 9. What side corresponds to side NO and can be used to show that ΔMNO ≅ ΔPQ
2 answers:
Answer:
QR is the side corresponds to side NO.
Step-by-step explanation:
SSS(Side-Side-Side) Postulates states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.
Given: Side MN= 6 units , OM = 9 units , PQ = 6 units and RP = 9.
In triangle MNO and triangle PQR
MN = PQ = 6 units [Side]
OM = RP = 9 units. [Side]
NO = QR [Side]
Then; by SSS postulates
Therefore, the sides which corresponds to side NO is, QR .
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Answer:
The equivalent to one over five m − 20 is one over five (m − 100) ⇒ B
Step-by-step explanation:
Let us solve the question
∵ One over five means
∴ One over five m - 20 = m - 20
→ By using the distributive property, take one over five as a common factor
from both terms
∴ m - 20 =
-
→ Simplify the bracket
∵ m ÷
=
m × 5 = m
∵ 20 ÷ = 20 × 5 = 100
∴
-
=
(m - 100)
∴ m - 20 =
(m - 100)
The equivalent to one over five m − 20 is one over five (m − 100)
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Suppose Micah invests x money. Then, we have that after 14 years, the capital available will be C=
. We have that C=18500$ and hence that 18500=x*1.562. Thus, solving for x we have that x=11841$.
Micah will need to invest only 11841$ in order to pay for his boat; this shows the importance of saving since he earns a lot of money, around 7k $.
Suppose Micah invests x money. Then, we have that after 14 years, the capital available will be C=
Micah will need to invest only 11841$ in order to pay for his boat; this shows the importance of saving since he earns a lot of money, around 7k $.