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const2013 [10]
2 years ago
12

Find the value of x. write your answer in simplest radical form

Mathematics
2 answers:
BartSMP [9]2 years ago
8 0

Answer:

<h2>x = 4 \sqrt{2}</h2>

Step-by-step explanation:

To find the value of x we can use either sine or cosine

Using cosine we have

<h3>\cos(\theta)  =  \frac{adjacent}{hypotenuse}</h3>

From the question

x is the hypotenuse

4 is the adjacent

We have

<h3>\cos45=  \frac{4}{x}  \\ x \cos45 = 4 \\ x =  \frac{4}{ \cos(45) }</h3>

We have the final answer as

<h3>x = 4 \sqrt{2}</h3>

Hope this helps you

Vitek1552 [10]2 years ago
4 0

Step-by-step explanation:

Sinø=opp/hyp

Sin45=4/x. (× b.s by x)

xSin45=4. (÷ b.s by Sin 45)

x=4/Sin45

x=4.7

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Which of the following values has 3 significant figures?
Wittaler [7]

Answer: D. al of the above

Step-by-step explanation:

the numbers 1-7 are the significant figures, and if there is a zero but still three numbers ranging from 1-7, it counts

4 0
3 years ago
Read 2 more answers
Matthew has a savings account that gives 1.5 interest. If he keeps it open for 5 years and it has a balance of 2000 how much in
pochemuha

Answer:

15187.5=2000(1.5)^5

Step-by-step explanation:

So right now he has 2000 in his saving each year it grows by 1.5 so by year 5 it should be

15187.5 in his savings

hope I did it right

6 0
2 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
Subtract these polynomials.
Artist 52 [7]

Answer:

The correct answer is D. 3x² - x + 3

Step-by-step explanation:

4x² - x + 6 - (x² + 3)

= 4x² - x² - x + 6 - 3

= 3x² - x + 3

5 0
2 years ago
brainliest goes to whoever answers the question correctly also if you want more points answer my other questions
Sergeeva-Olga [200]

Answer:

A and B are functions

Step-by-step explanation:

for A, none of the x's repeat which makes it a FUNCTION

for B, when it starts with x^2, it will always be a FUNCTION (its a quadratic)

for C, 10 repeats for the x so it is NOT A FUNCTION

4 0
2 years ago
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