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4 years ago

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Angles in a triangle: I did common like terms: 2x+190=180. I solved it and got -10. I checked my answer by changing x to -10. I

solved it and got 180. or

2 answers:

tatyana61 [14]4 years ago

8 0

Minus 180 from 190. You have -10
2x= -10
Which means x equals -5

netineya [11]4 years ago

7 0

That's correct. Now you gotta plug in -5 in for x and get both angles.

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The numbers of home runs that Barry Bonds hit in the first 18 years of his major league baseball career are listed below. Find t

vekshin1

Answer:

Mean = 35.56

Median = 35.5

Step-by-step explanation:

Given the data:

16 25 24 19 33 25 34 46 37

33 42 40 37 34 49 73 46 45

Reordered data :

16, 19, 24, 25, 25, 33, 33, 34, 34, 37, 37, 40, 42, 45, 46, 46, 49, 73

The mean = ΣX / n

n = sample size ; ΣX = sum of values

The mean = 658 / 18

The mean = 36.56

The Median = 1/2(n+1)th term

1/2(18+1)th term = 1/2(19)th term = 9.5 term

Median = (9th + 10th) / 2 = (34 + 37) / 2 = 35.5

3 0

3 years ago

HELP PLZ REALLY NEED IT

NISA [10]

The formula for the surface area is given and as follows.

SA = (2)(3.14)(r^2) + (2)(3.14)(r)(h)

The radius of the cylinder is 4 inches and the height is 9 inches. Using the given values, we can plug them into the formula and solve for the surface area from there.

SA = (2)(3.14)(4^2) + (2)(3.14)(4)(9)

SA = (6.28)(16) + (6.28)(36)

SA = 100.48 + 226.08

SA = 326.56 in^2

Hope this helps!! :)

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4 years ago

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The circle below is centered at the point (1, 2) and has a radius of length 3.

Vitek1552 [10]

The equation is (x-1)^2+(y-2)^2=81

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4 years ago

What is the value of X in the equation 3x(x-10)+7x=1/2(12x-4)

Flauer [41]

Answer:

x = 29/6 + 1/ 6 √817 or x = 29/ 6 + −1/ 6 √817

Step-by-step explanation:

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3 years ago

The n × n identity matrix is the matrix with diagonal entries are all 1’s and the rest are all 0’s. Show that, for any n×n matri

Tatiana [17]

Express the matrix $I$ like $(\delta_{ij})_{n\times n}$ , where $\delta_{ij}=1$ if $i=j$ and $\delta_{ij}=0$ if $i\neq j$ . ( $\delta_{ij}$ is known as kronecker's delta)

In the same form we express the matrix $A=(a_{ij})_{n\times n}$ .

The firs index indicate the row and the second the column.

By the multiplication of matrices we have $AI=(c_{ij})_{n\times n}$ , where

$c_{ij}=\sum_{k=1}^n a_{ik}\delta _{kj} = a_{ij}$

because only $\delta_{jj}$ is non-zero in the last sum.

therfore we have $AI=(c_{ij})_{n\times n}=(a_{ij})_{n\times n}=A$ .

In the same manner we have

$IA=(d_{ij})_{n\times n}$ , where

$d_{ij}=\sum_{k=1}^n \delta _{ik}a_{kj} = a_{ij}$

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3 years ago