We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
69.75
I hope this helped you out!!
Answer:
79
Step-by-step explanation:
(237)(1/3) = 79
Answer:
hihihihihihihihihihihihihihi
the length of a leg on a 45-45-90 triangle given the hypotenuse is half the length of the hypotenuse times sqrt(2)
hypotenuse = 10
10/2 =5
so the answer should be 5sqrt(2), which I don't see as a choice
