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Pachacha [2.7K]
2 years ago
5

WILL GIVE BRAINLIEST Solve for x

Mathematics
1 answer:
myrzilka [38]2 years ago
8 0

Answer:

Step-by-step explanation:

sin x° = \frac{17}{19}

x° = sin^{-1} \frac{17}{19}

x° ≈ 63°

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If A = {1, 2, 3} and B = {1, 2, 2, 3}, is B ⊆ A? If so, is A = B?
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yes, yes

Step-by-step explanation:

B={1,2,3} it doesn't matter if it has ten 2's or one!

so A=B and A⊆B

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Find the value of the variable and the measure of each labeled angle.
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x+10

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When StartFraction 2 x squared Over y EndFraction = StartFraction w + 2 Over 4 EndFraction is solved for w, one equation is w =
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the first one

Step-by-step explanation:

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2 years ago
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Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

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Which of the following Triangle cases cannot be solved, using either the law of cosines or law of sines
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