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timofeeve [1]
3 years ago
15

Original price of a CD is $17.50 discount is 50%​

Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

$8.75

Step-by-step explanation:

To calculate this you could use two methods. The first method is to find out what 10% is and multiply it by 5. The second method is to calculate 50% using the formula.

<u>Method 1:</u>

To work this out you would simply divide 17.50 by 10, which is 1.75. This is because percentages are out of 100 and so by dividing by 10 we are finding out what 10% is. Then you would multiply 1.75 by 5, which is 8.75. Then you would minus 8.75 from 17.50, which is 8.75.

<u></u>

1) Divide 17.50 by 10.

17.50/10=1.75

2) Multiply 1.75 by 5.

1.75*5=8.75

3) Minus 8.75 from 17.50.

17.50-8.75=8.75

4) The new price is $8.75

<u>Method 2:</u>

<u></u>

The formula for percentages is.

\frac{percentage}{100} * amount

<u></u>

To work this out you would first divide 50 by 100, which gives you 0.5. Then you would multiply 0.5 by 17.50, which is 8.75. Then you would minus 8.75 from 17.50, which is 8.75.

1) Divide 50 by 100.

50/100=0.5

2) Multiply 0.5 by 17.50.

17.50*0.5=8.75

3) Minus 8.75 from 17.50.

17.50-8.75=8.75

4) The new price is $8.75.

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The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.
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Answer:

Given the equation: 3x^2+10x+c =0

A quadratic equation is in the form: ax^2+bx+c = 0 where a, b ,c are the coefficient and a≠0 then the solution is given by :

x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a} ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}

Simplify:

x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}

Also, it is given that the difference of two roots of the given equation is 4\frac{2}{3} = \frac{14}{3}

i.e,

x_1 -x_2 = \frac{14}{3}

Here,

x_1 = \frac{-10 + \sqrt{100- 12c}}{6} ,     ......[2]

x_2= \frac{-10 - \sqrt{100- 12c}}{6}       .....[3]

then;

\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}

simplify:

\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}

or

\sqrt{100- 12c} = 14

Squaring both sides we get;

100-12c = 196

Subtract 100 from both sides, we get

100-12c -100= 196-100

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve x_1 , x_2

x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}

or

x_1 = \frac{-10 + \sqrt{100- 96}}{6} or

x_1 = \frac{-10 + \sqrt{4}}{6}

Simplify:

x_1 = \frac{-4}{3}

Now, to solve for x_2 ;

x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}

or

x_2 = \frac{-10 - \sqrt{100- 96}}{6} or

x_2 = \frac{-10 - \sqrt{4}}{6}

Simplify:

x_2 = -2

therefore, the solution for the given equation is: -\frac{4}{3} and -2.


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