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Jobisdone [24]
3 years ago
9

How do you put 300,000+10,000+6,000+20+9

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

three hundred thousand plus ten thousand plus six thousand plus twenty plus nine

Step-by-step explanation:

300,000 → three hundred thousand

10,000 → ten thousand

6,000 → six thousand

20 → twenty

9 → nine

+ → plus

Now put everything together.

Best of Luck!

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HELP PLS
AlladinOne [14]

Answer:

e

Step-by-step explanation:

Part A: 10 + m = t

Extra money earned on Thursday = m

Total money earned = t

Part B: 2x + 2

we have no idea how many dogs silas walked

x = amount of dogs silas walked

uh this one wasn't that good

either way, hope this helped :)

5 0
2 years ago
Read 2 more answers
Let's find +1418.
zysi [14]

Answer:

u just explained ur answer

Step-by-step explanation:

7 0
2 years ago
Rearrange the formula a = v^2/ r for v
BabaBlast [244]
Isolate the v.

a = v^2/2

First multiply 2 to both sides

a(2) = v^2/2(2)

2a = v^2

Isolate the v, root both sides

√2a = √v^2
✓2a = v

✓2a = v should be your answer


Hope this helps
7 0
3 years ago
Change 2.56 into a percentage *<br><br> 0.0256%<br> 25.6%<br> 256.0%<br> none of the above
Ksivusya [100]

Answer:

C: 256%

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack). Suppose we have
Sonbull [250]

The probability solved by binomial distribution that all will survive is 0.8154.

<h3>What is Binomial distribution? </h3>

When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Computation of probability of all survived people from heart attack;

A heart attack patient has a 0.04 percent chance of dying from the attack (i.e., 4 of 100 die of the attack).

What is the likelihood that each of the five patients who experience a heart attack will survive?

We'll refer to a victory in this scenario as a heart attack (p = 0.04). In other words, we are interested in the likelihood that none of our n=5 patients will die (0 successes).

Each attack has a chance of being fatal or not, with a probability of 4 percent for all patients, and each patient's result is independent.

Assume for the purposes of this example that the five individuals being examined are unrelated, of the same age, and free of any concomitant disorders.

By binomial distribution,

\begin{gathered}P(0 \text { successes })=\frac{5 !}{0 !(5-0) !} 0.04^{0}(1-0.04)^{5-0} \\P(0 \text { successes })=\frac{5 !}{5 !}(1)(0.96)^{5}=(1)(1)(0.8154)=0.8154\end{gathered}

Therefore, with a 4 % chance that anyone will die, there is an 81.54% chance that every patient will survive the onslaught. The outcomes in this example could be 0, 1, 2, 3, 4 or 5 successes (fatalities).

To know more about Binomial Distribution, here

brainly.com/question/27794898

#SPJ4

6 0
1 year ago
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