Answer:
30.49 m
Step-by-step explanation:
To obtain the maximum height, we solve for the value x when dy/dx = 0.
Since, y = -5x² + 40x + 20
dy/dx = d[-5x² + 40x + 20]/dx
dy/dx = -10x + 40
Since dy/dx = 0,
-10x + 40 = 0
-10x = -40
x = -40/-10
x = 4
Substituting x = 4 into the equation for y, we have
y = -5x² + 40x + 20
y = -5(4)² + 40(4) + 20
y = -5(16) + 160 + 20
y = -80 + 160 + 20
y = 80 + 20
y = 100 ft
Since y is in feet, we convert to meters.
Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m
So, the maximum height, in meters reached by the projectile is 30.49 m
Step-by-step explanation:
no it's not.....
........
Answer:71
Step-by-step explanation:
range is the difference between the highest number and the smallest number in a group of data
Highest number=85
Smallest number=14
Range=highest number-smallest number
Range=85-14
Range=71
Answer:
30 cubes are added
Step-by-step explanation:
The image of the solid shape is attached.
From the Plan, Side elevation and Front elevation, the number of cubes needed to make the shape is 18 blocks. From the front elevation, 12 blocks is needed (4 * 3 blocks) while from the side elevation 6 blocks are needed given a total of 18 blocks.
The number of blocks needed to make the cuboid = 4 * 4 * 3 = 48 cm cubes.
Therefore the number of cubes to be added = 48 cubes - 18 cubes = 30 cubes.
30 cubes are added