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Salsk061 [2.6K]
3 years ago
11

Which one is this answer if you are good a math

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

a=\dfrac{2d}{t^2}\ \ \ \ \ |\text{solve for t} \\ \\\\\dfrac{2d}{t^2}=\dfrac{a}{1}\ \ \ \ \ |\text{cross multiply}\\\\at^2=2d\ \ \ \ \ |:a\\\\t^2=\dfrac{2d}{a}\to t=\sqrt{\dfrac{2d}{a}}\\\\\text{We have}\\ \\a=2\dfrac{m}{s^2},\ d=10m\\\\\text{substitute}\\\\t=\sqrt{\dfrac{2\cdot10m}{2\frac{m}{s^2}}}=\sqrt{10m\cdot\dfrac{s^2}{m}}=\sqrt{10s^2}=\sqrt{10}\ s\\\\Answer:\ C.\ \sqrt{10}\ seconds

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