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daser333 [38]
3 years ago
11

What is 17/5 as a mixed number in simplest form?

Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Note that you take out whatever can be a whole number, and leave the rest over the denominator

5 x 3 = 15

17 - 15 = 2

3 2/5 is your answer in simplest form (as it cannot be simplified anymore)

hope this helps

finlep [7]3 years ago
8 0

To find what 17/5 is as a mixed number in simplest form, we can first see if we can simplify the fraction. Since both of the numbers are prime, we can see that we cannot simplify the improper fraction any further.

Now, we have to turn 17/5 into a mixed number. To turn 17/5 into a mixed number, we must first find out how many times 5 goes into 17. 5 goes into 17 3 times, and has a remainder of 2.

That means that the whole part of the mixed number is 3. Since there is a remainder of 2 when five goes into 17, the numerator of the fractional part of the mixed number is 2. In addition, since we are dividing by 5, the denominator of the fraction is 5, meaning that the fraction is 2/5.

That means that our answer is 3 2/5

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The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

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<h3>Specific Gravity</h3>

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Learn more on specific gravity here;

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