The original value was <span>£720.
720 x .15 (15%) = 108
720 + 108 = 828 </span>
Q1
I like to use the standard form to write the equation of a perpendicular line, especially when the original equation is in that form. The perpendicular line will have the x- and y-coefficients swapped and one negated (remember this for Question 3). Thus, it will be
... 5x - 2y = 5(6) - 2(16) = -2
Solving for y (to get slope-intercept form), we find
... y = (5/2)x + 1 . . . . . matches selection C
Q2
The given equation has slope -3/6 = -1/2, so that will be the slope of the parallel line. (matches selection A)
Q3
See Q1 for an explanation. The appropriate choice is ...
... B. 4x - 3y = 5
Q4
The given line has slope -2, so you can eliminate all choices except ...
... D. -2x
Q5
The two lines have the same slope (3), but different intercepts, so they are ...
... A. parallel
Answer:
a) amount in the bank after 7 years if interest is compounded quarterly is $6,605
b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57
Step-by-step explanation:
We are given:
Principal Amount P= 5000
Rate r= 4% = 0.04
time t = 7 years
The formula used is: 
where A is future value, P is principal amount, r is rate, n is compounded value and t is time
a) Find the amount in the bank after 7 years if interest is compounded quarterly?
If interest is compounded quarterly then n = 4
Using values given in question and finding A

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605
b) Find the amount in the bank after 7 years if interest is compounded monthly?
If interest is compounded quarterly then n = 12
Using values given in question and finding A

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57