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svp [43]
3 years ago
7

Which of the following options have the same value as 10% of 33?

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0
Answers: C D E

If you have any questions, please ask me
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Step-by-step solution for: (√2+√10)^2
azamat
Note:  √a * √a  = a
           √a * √b  = √ab

(√2 + √10)²  =  (√2 + √10)(√2 + √10)
                    =  √2(√2 + √10) + √10(√2 + √10)
                    =   √2*√2 + √2*√10 + √10*√2 + √10*√10
                    =       2      + √20  + √20 + 10
                    =      (2 + 10) + (√20 + √20)
                    =        12 +  2√20

√20 = √(4 *5) = √4 * √5 = 2√5

                     =        12 +  2√20  = 12 + 2(2√5)
                     = 12 + 4√5
5 0
3 years ago
Mr. Palmer deposited $850 into a simple interest account for 8 years, earning at an 8% interest rate. What will his total balanc
Andrei [34K]

Answer:

solution given:

principal [P]=$850

time[T]=8years

rate[R]=8%

now

simple interest [S.I.]=\frac{P×T×R}{100} =$ \frac{850×8×8}{100} =$544

so

Total balance=S.I.+P=$544+$850=$1394.

<u>option b.$1,394.00 is your answer</u>

6 0
3 years ago
Can someone answer this easy question 46 plus what equals 77
Reika [66]

Answer:

Step-by-step explanation:

46+x=77 subtract 46 from both sides

x=31

4 0
3 years ago
Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Stells [14]

Answer:

f(x) =  {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x  \rightarrow \: x = sec \: y\\  \frac{dx}{dx}  =  \frac{d(sec \: y)}{dx}  \\ 1 = \frac{d(sec \: y)}{dx} \times  \frac{dy}{dy}  \\ 1 = \frac{d(sec \: y)}{dy} \times  \frac{dy}{dx}  \\1 = tan \: y.sec \: y. \frac{dy}{dx}  \\ \frac{dy}{dx} =  \frac{1}{tan \: y.sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ \sqrt{( {sec}^{2}   \: y - 1}) .sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\   \therefore  \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx}  =  \frac{1}{ |5x |  \sqrt{25 {x }^{2}  - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} }

4 0
2 years ago
Ya'll I'm desperate please answer this I really need to get it right.
IceJOKER [234]

Answer:

a. Indep. = x, and dependent equals f(x)

b. x impacts f(x)

f(-4)= -11

Step-by-step explanation:

hope this helped

4 0
2 years ago
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