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Phantasy [73]
3 years ago
13

Help me please, thank u

Mathematics
2 answers:
IrinaVladis [17]3 years ago
4 0

Answer:

B. 76 square centimeters

ella [17]3 years ago
3 0

Answer: 76 square cm

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which of the following polynomials has a graph with odd symmetry? a. 7x^4+13x^3-11 b. 5x^7+4x^6+3x^5+x c.13x^5 -1/2x^3+7x+3 d. 8
agasfer [191]

Answer: 45x3x345!3

Step-by-step explanation:

you multiply all numbers then you divide by all the numbers there and there’s your answer

6 0
2 years ago
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At the nearest wholesale store, 3 bags of bulk cereal cost $21.75. At this rate, how much would 5 bags of bulk cereal cost?
sertanlavr [38]

Answer:

if three bags cost $21.75, one bag costs $7.25, therefore five bags cost $36.24.

Hope this helped!

Step-by-step explanation:

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3 years ago
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The yearly attendance at a local movie theater is 68,000 and grows continuously at a rate of 3.5% each year what is the approxim
asambeis [7]

3.5 \times 8 - 68000
the answer is 67972
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3 years ago
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Suppose <img src="https://tex.z-dn.net/?f=m" id="TexFormula1" title="m" alt="m" align="absmiddle" class="latex-formula"> men and
ollegr [7]

Firstly, we'll fix the postions where the n women will be. We have n! forms to do that. So, we'll obtain a row like:

\underbrace{\underline{~~~}}_{x_2}W_2 \underbrace{\underline{~~~}}_{x_3}W_3 \underbrace{\underline{~~~}}_{x_4}... \underbrace{\underline{~~~}}_{x_n}W_n \underbrace{\underline{~~~}}_{x_{n+1}}

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m~~~(i)

Since there is no women sitting together, we must write that x_2,x_3,...,x_{n-1},x_n\ge1. It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

\begin{cases}x_2=x_2'+1\\x_3=x_3'+1\\...\\x_{n-1}=x_{n-1}'+1\\x_n=x_n'+1\end{cases}

The equation (i) can be rewritten as:

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m\\\\&#10;x_1+(x_2'+1)+(x_3'+1)+...+(x_{n-1}'+1)+x_n+x_{n+1}=m\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-(n-1)\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-n+1~~~(ii)

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: \dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}

[I can write the proof if you want]

Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: m!

Multiplying all results:

n!\times\dfrac{(m+1)!}{n!(m-n+1)!}\times m!\\\\&#10;\boxed{\boxed{\dfrac{m!(m+1)!}{(m-n+1)!}}}

4 0
3 years ago
Carol drives her daughter to school at an average rate of 30 miles per hour, but only goes an average rate of 20 miles per hour
Ivahew [28]
<span>24 mph

</span>P.S. please vote this as the brainliest answer :)
6 0
3 years ago
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