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tekilochka [14]
3 years ago
11

If the exterior sides of two adjacent angles are opposite rays, then the angles are _____ angles.

Mathematics
2 answers:
Kipish [7]3 years ago
6 0

Answer supplementary

Step-by-step explanation:

elena-s [515]3 years ago
4 0
The correct answer is B. Supplementary

That is the basic definition of what supplementary angles are and can be found in any textbook.
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FromTheMoon [43]

Answer:

18=2^x

Step-by-step explanation:

log_2(18)=x\\\\2^{log_2(18)}=2^x\\\\18=2^x

4 0
2 years ago
Read 2 more answers
use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11
Evgen [1.6K]
So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1

so... what' the point h,k for the center?  well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"?  well, "b" comes from the conjugate axis, or the other runnning over the x-axis   hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is  \bf c=\sqrt{a^2+b^2}

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus  \bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b

that'd be "b"

bearing in mind that   \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}
\end{cases}

8 0
3 years ago
how do you know if your anwser in absolut value is extranious after you plug it back into the equation?
Ivanshal [37]
If an number is an absolute value, it means that the number will be positive. You would plug and check the same way you would for any other equation and it a solution is considered extraneous if the equation is not equal
4 0
3 years ago
What are the solutions of the quadratic equation? 2 x^2 – 16 x + 32 = 0
White raven [17]

Answer:

X=4,4

Step-by-step explanation:

2 x^2 – 16 x + 32 = 0

2(x^2-8x+16)=0

X^2-(4+4)X+16=0

x^2-4x-4x+16=0

x(x-4)-4(x-4)=0

(x-4)(x-4)=0

X=4,4

So the solution is X=4,4

3 0
3 years ago
What is the vaule of 3.85+0.004+0.117 ?
Darya [45]
<span>3.85+0.004+0.117=3.971</span>
5 0
3 years ago
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