Answer:
Factor 3y23y2 out of 3y33y3.
3y2(y)−9y23y2(y)-9y2
Factor 3y23y2 out of −9y2-9y2.
3y2(y)+3y2(−3)3y2(y)+3y2(-3)
Factor 3y23y2 out of 3y2(y)+3y2(−3)3y2(y)+3y2(-3).
3y2(y−3)
Step-by-step explanation:
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The solution (x,y) needs to work in both equations. With multiple choice you can do guess and test method. Otherwise you need to combine the two equations into one by substitution or elimination methods.
21. substitution works well here since one equation is y= x+3. you can easily substitute the (x+3) for y in the other equation.
2x + (x+3) = -6
3x + 3 = -6
3x = -9
x = -3
use this in either equation to find y.
y = (-3)+3
solution: (-3,0)
22. these both equal y so they equal each other.
4x - 1 = 3x +6
4x - 3x = 6 + 1
x = 7
use this in either equation to find y
y = 4(7) - 1
y = 28 - 1
y = 27
solution: (7,27)
23. one equation is y = 2x - 3. So substitute (2x -3) for y in the other equation.
4x = 2(2x - 3) + 6
4x = 4x - 6 + 6
4x = 4x
x = x
any solution will work, infinitely many.
24. infinitely many solutions means the two equations are the same equation. Like the previous one they didn't look the same but if you put them both in terms of y...
y= 2x-3
4x = 2y + 6
4x - 6 = 2y
(4x - 6)/2 = y
2x - 3 = y
same equation.
from the image, I can't see all options but A & C do not look like the same equations. It's got to be either B or D.
Answer:
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Step-by-step explanation:
Answer:
The answer is eight.
All you have to do is graph the points and count how many boxes are inside the points.