So, x = 13, x = √3 and x =7i.
now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value "a", that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.
now.... keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 - 7i, which is the other root.
In solving algebraic expressions, there is an order in which to solve it.
1) perform the operation inside the parenthesis first
2) then perform the operation with the exponents
3) apply multiplication and division from left to right of the equation.
4) apply addition and subtraction from left to right of the equation.
Remember this: PEMDAS for easier recall. (parenthesis, exponents, multiplication, division, addition, subtraction)
Answer:
38.5
Step-by-step explanation:
First do 77/2 then you get 38.5, if anything is wrong please tell me!!
21-8=13 so hope that helps x
Answer: (-2, 2) and (4, 8)
There are two solutions because the two functions cross each other twice.