<h2>1.</h2>
So remember that with more than one pair of parentheses, you have to start from the inside and make your way outside.
Firstly, on the left side, solve 5+2 and on the right side solve 4 × 3:
![4[3(7)]=95-12](https://tex.z-dn.net/?f=4%5B3%287%29%5D%3D95-12)
Next, on the left side, solve 3 × 7 and on the right side solve the subtraction:
![4[21]=83](https://tex.z-dn.net/?f=4%5B21%5D%3D83)
Lastly, solve the remaining multiplication on the left side and the answer is 
<u>Since 84 is not equal to 83, the correct answer is the second option.</u>
<h2>2.</h2>
For this, plug 5 into the z variable to solve.

<u>Since 15 = 15 is true, your answer is the first option.</u>
<h2>3.</h2>
So for this, it's a similar process as Question 2 except that you are plugging in 0 into the x variable to solve:

<u>Since 8 = 0 is a false statement, the correct answer is the second option.</u>