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Irina-Kira [14]
3 years ago
5

Quick question about area -

Mathematics
1 answer:
solniwko [45]3 years ago
7 0
The amount of paper used to make the model is 30.8 centimeters. But, I'm not sure.
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PLEASE HELP ITS URGENT
Monica [59]

Answer:

( -4, 3 )

Step-by-step explanation:

The solution is where the lines cross.

8 0
3 years ago
Read 2 more answers
Tonya cuts 3 feet from a 5​-foot length of rope. Then she cuts 18 inches from the rope. How many inches of rope are​ left?
gogolik [260]

Answer:

6

Step-by-step explanation:

12 inches in a foot

12x5= 60

3x12=36

60-36=24

24-18=6

Hope this helps!

3 0
3 years ago
Read 2 more answers
I really need some help. Serious and correct answers please I appreciate it.
mezya [45]

Answer:

A. You need to draw a straight line that increases from left to right. Try and get the same amount of plots on the top and bottom of the line and go through one or two of the plots. Don't connect the dots, though.

B. This scatter plot demonstrates a positive association between a person's height and weight because the trendline increases from left to right. According to this data, as weight increases, so does height. The more someone weighs, the more likely they are to be tall.

7 0
2 years ago
If a cheetah runs for 4 seconds and runs 120 meters, how many seconds does it take a cheetah to run 270 meters? Explanation Plea
seraphim [82]

Answer:

<em>The cheetah needs 9 seconds to run 270 meters</em>

Step-by-step explanation:

<u>Proportions</u>

Given the rate of change of the distance traveled by a cheetah is constant, we can predict the time taken to travel any distance.

The cheetah runs 120 for 4 seconds. The rate of change is:

\frac{120\ m}{4\ s}=30\ m/s

This is the cheetah's speed.

To run 270 meters, we divide the distance by the speed to find the time:

t=\frac{270}{30}=9

The cheetah needs 9 seconds to run 270 meters

8 0
3 years ago
Help me plz I need help
makkiz [27]

Answer:

x = 14°

Step-by-step explanation:

x + 76° = 90°

or, x = 90° - 76°

so, x = 14°

8 0
3 years ago
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