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Finger [1]
3 years ago
14

Please help with this 1 question. 25 points

Mathematics
1 answer:
Elza [17]3 years ago
5 0
Yes no question one and no for question 2
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If you can explain your answer that’d be great!! Thank you!
Rasek [7]

Answer:

A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

A(t)=A_{0}e^{kt}

Where

k=\frac{ln(\frac{1}{2})}{Half-Life}

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}

Now

A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

third choice is correct.

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