Help me with number 13 and 14 in he pictures

Mathematics

2 answers:

Goryan [66]3 years ago

7 0

11 is South Africa because if its 60.3 when its LOW then it would be really high if it was the high temp

arsen [322]3 years ago

3 0

I don't know about 13 but 14 is Chicago I'm pretty sure

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The length of a rectangle is 2 less than twice the width. The perimeter of the rectangle is 38. Find the length and the width of

hjlf

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6 0

3 years ago

I need help with b. please

aniked [119]

Its 1/5,

35/100 - 15/100 = 20/100

for 20, 40, 60, 80, 100
1, 2, 3, 4, 5

so 20/100 = 1/5

8 0

3 years ago

I need to solve for x - 6(2x-5)=-(x+4)

sdas [7]

Distribute
x-12x+30=-x-4

Combine like terms
-11x+30=-x-4

Add x to both sides
-10x+30= -4

Subtract 30 from both sides
-10x=-34

Divide both sides by -10
x=3.4

Final answer: x=3.4

7 0

3 years ago

Read 2 more answers

Integrate e^x(sin(x) cos(x))

Karo-lina-s [1.5K]

$I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx$

$\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
\text{Using }\int u\,dv=uv-\int v\,du:\\\\
I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\
2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}$

Looking for $I_2$ :

$\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I$

Replacing:

$2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\
2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\
10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\
I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\
\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}$

6 0

3 years ago

I need help finding the answer to this:

anygoal [31]

Answer:

He will earn $6 in interest in 9 months.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

$T = E + P$