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Lubov Fominskaja [6]
3 years ago
14

Help me with number 13 and 14 in he pictures

Mathematics
2 answers:
Goryan [66]3 years ago
7 0
11 is South Africa because if its 60.3 when its LOW then it would be really high if it was the high temp
arsen [322]3 years ago
3 0
I don't know about 13 but 14 is Chicago I'm pretty sure

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The length of a rectangle is 2 less than twice the width. The perimeter of the rectangle is 38. Find the length and the width of
hjlf

Answer:

YEET A DOG

Step-by-step explanation:

YEETING A DOG GIVES U COOL POINTS LOLOLOLOLOLOLOLOLOLOLOL

6 0
3 years ago
I need help with b. please
aniked [119]
Its 1/5, 

35/100 - 15/100 = 20/100

for 20, 40, 60, 80, 100
      1,   2,   3,   4,   5

so 20/100 = 1/5
8 0
3 years ago
I need to solve for x - 6(2x-5)=-(x+4)
sdas [7]
Distribute
x-12x+30=-x-4

Combine like terms
-11x+30=-x-4

Add x to both sides
-10x+30= -4

Subtract 30 from both sides
-10x=-34

Divide both sides by -10
x=3.4

Final answer: x=3.4
7 0
3 years ago
Read 2 more answers
Integrate e^x(sin(x) cos(x))
Karo-lina-s [1.5K]
I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx

\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
\text{Using }\int u\,dv=uv-\int v\,du:\\\\
I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\
2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}

Looking for I_2:

\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\  I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I

Replacing:

2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\
2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\
10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\
I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\
\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}
6 0
3 years ago
I need help finding the answer to this:
anygoal [31]

Answer:

He will earn $6 in interest in 9 months.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

T = E + P

Initial deposit of $400.

This means that P = 400

2% annual interest

This means that I = 0.02

How much interest will he earn in 9 months?

An year has 12 months, this means that t = \frac{9}{12} = \frac{3}{4} = 0.75

This is E. So

E = P*I*t = 400*0.02*0.75 = 6

He will earn $6 in interest in 9 months.

8 0
3 years ago
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