Answer: Infinitely many solutions.
Step-by-step explanation:
The correct pair is option E, which is:
FH ≅ FH - reflexive property
ΔGFH ≅ ΔEFH - SAS theorem
<h3>What is the SAS Congruence Theorem?</h3>
The SAS theorems states that two triangles are congruent if they have two pairs of congruent sides and a pair of congruent included angles.
<h3>What is the Reflexive Property?</h3>
The reflexive property of geometry states that an angle or line will always be congruent to itself.
In the two column-proof, since FH = FH using the reflexive property, then both triangles are congruent to each other by the SAS congruence theorem.
The missing pair of reasons that completes the proof are:
FH ≅ FH - reflexive property
ΔGFH ≅ ΔEFH - SAS theorem
Learn more about the SAS theorem on:
brainly.com/question/2102943
#SPJ1
the answer should be letter A
the difference of 3.4 and 1.25 = 2.15
Now you know that there will be 2 whole blocks and .15 of a block
.15 is equal to 3/20 which is equal to 15/100.
So you will have 2 whole blocks and 15/100 of a blocks. So the answer is A
Answer:
slope is -2 and the y-intercept is 12
Step-by-step explanation:
a key thing to remember: x is always equal to 0 when finding the y-intercept.
so if you look at the table for where 0 is, you get the point (0,12) meaning the y-intercept is 12.
to find the slope use the equation: slope= change in y/change in x
you can use any two points to find this.
lets take the points of the x-intercept (6,0) and the y-intercept (0,12)
12-0/0-6
12/-6
-2 = slope
Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:

Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:

2. Charlene's rhombus:

Dividing the area calculated, you get:

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.