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3 years ago

A toy plush weighed 1/5 of a pound. a flimsy box can hold 3 pounds. how many toy plushes could the box hold?

1 answer:

4 0

So how many 1/5 pounds can a box, that holds 3 pounds, hold?
total weight = 1/5 times the amount of toys
3 = 1/5 x
rewrite
3 = 1x /5
multiply both sides by 5
15 = 1x
15 = x <span>

The flimsy box can hold 15 toy plushes.

Hope this helps</span>

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3 years ago

Suppose the probability that a softball player gets a hit in any single at-bat is 0.300. Assuming that her chance of getting a h

Ksivusya [100]

Answer:

$P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103$

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

Solution to the problem

For this case we want this probability

$P(X=4)$

And using the probability mass function we got:

$P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103$

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

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3 years ago