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2 years ago

If you explain and answer i will give brainly

Mathematics

1 answer:

CaHeK987 [17]2 years ago

7 0

6x - 5y = 3 x1

3x - 8y = -15 x2

===============

6x - 5y = 3

6x - 16y = -30

============= -

11y = 33

y = 3

6x - 5(3) = 3

6x -15 = 3

6x = 18

x = 3

(3,3)

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It looks like the system is

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Let $\eta_1 = 1-2i$ ; then $\eta_2=1$ , so that

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$\implies \begin{cases}a - 5c + d = 1 \\ b - c + d = 0 \\ 5a - b + c = 0 \\ a - b + d = -2 \end{cases} \implies a=\dfrac{11}{41}, b=\dfrac{38}{41}, c=-\dfrac{17}{41}, d=-\dfrac{55}{41}$

Then the general solution to the system is

$x = C_1 e^{2it} \begin{bmatrix} 1 - 2i \\ 1 \end{bmatrix} + C_2 e^{-2it} \begin{bmatrix} 1 + 2i \\ 1 \end{bmatrix} + \dfrac1{41} \cos(t) \begin{bmatrix} 11 \\ 38 \end{bmatrix} - \dfrac1{41} \sin(t) \begin{bmatrix} 17 \\ 55 \end{bmatrix}$

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In the question, we are asked about the different dinner meals possible when a dinner meal is made up of an appetizer, a main course, a dessert, and a drink.

The choices for the appetizer are soup or salad, so the number of ways of choosing an appetizer = 2C1 = 2.

The choices for the main course are chicken, fish, steak, or lobster, so the number of ways of choosing a main course = 4C1 = 4.

The choices for the dessert are ice cream, pie, sorbet, or pastry, so the number of ways of choosing a dessert = 4C1 = 4.

The choices for the drink are coffee, tea, or milk, so the number of ways of choosing a drink = 3C1 = 3.

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The number of different meals possible is 96, computed using combinations.

Learn more about combinations at

brainly.com/question/11732255

#SPJ4

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