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yarga [219]
4 years ago
8

A farm is to be built in the shape of Quadrilateral ABCD, as shown below. All four sides are equal.

Mathematics
2 answers:
zlopas [31]4 years ago
5 0

Hello,

The correct answer is D) 102.3

Hope this helps!!!! (:

kompoz [17]4 years ago
4 0
The formula needed to find the area of a rhombus is (L1*L2)/2
(15.5*13.2)/2
204.6/2
102.3
The area of the farm of the 102.3
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(02.02 LC) Choose the equation that could be used to find three consecutive integers whose sum is 36. (5 points) n + (n + 2) + (
Annette [7]
<span>n + (n + 1) + (n + 2) = 36 Let's first create the equation ourselves and then see if it fits any of the available options. We want 3 consecutive integers that add up to 36. Let's use the value "n" to represent the first number in the sequence. n Now the next number will be n+1 and the third will be n+2. And since we want the sum, we get n + n + 1 + n + 2 = ? And finally, we want the sum to be 36, so our final equation is n + n + 1 + n + 2 = 36 With this equation in mind, let's look at the available choices. n + (n + 2) + (n + 4) = 36 Well, it has the 36 OK, but it has +2 and +4 where we have +1 and +2. So it won't fit and it's wrong. n + (n + 1) + (n + 3) = 36 Closer. Got the 36 and the +1. But it has +3 instead of +2, so not a fit either. n + (n + 1) + (n + 2) = 36 This looks good. Has a couple of extra parenthesis, but they don't affect the final answer and it has the +1, +2 and the 36. This one is correct. n + (n â’ 1) + (n â’ 3) = 36 Hmm. The n - 1 has a possibility. Perhaps they want n to be the middle of the 3 numbers to add. If that's the case, then the other number should be n+1 which it isn't. Maybe they want the n to be the last number. If that's the case, then the third number should be n-2. But that doesn't work either. So this equation won't work. So of the 4 choices, the only answer that works is "n + (n + 1) + (n + 2) = 36"</span>
5 0
4 years ago
Find S18 for geometric series given a5=-6 and a2= -48
Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4


a2 = a1 r^(2-1)

-48 = a1 r


divide

-6 =a1 r^4

----------------    yields   1/8 = r^3      take the cube root  or each side

-48 = a1 r                     1/2 = r


an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

-48 = a1 (1/2) ^1

divide by 1/2

-96 = a1


an = -96 (1/2)^ (n-1)


the sum

Sn = a1[(r^n - 1/(r - 1)]

S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]

       =-96 [ (1/2) ^ 17 -1 /-1/2]

      = 192 * [-131071/131072]

 approximately -192

     

       

     

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yKpoI14uk [10]
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kykrilka [37]
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