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serious [3.7K]
4 years ago
9

Chase halls health insurance cost $373.50 per month he must pay 25% of the amount and his employer pay 75% of the amount how muc

h does mr hall pay for health insurance each month
Mathematics
1 answer:
ZanzabumX [31]4 years ago
8 0

Answer:

$93.38

Step-by-step explanation:

To solve this, we simply multiple $373.50 by 25% to figure out how much Mr.Hall pays for health insurance each month. Don't forget that we need to change 25% to its decimal form (25% -> 0.25).

$373.50 x 0.25 = $93.38

Mr.Hall must pay $93.38 dollars a month for his health insurance.

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Task 2 a. Do some research and find a city that has experienced population growth. Determine its population on January 1st of a
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Exponential functions are functions defined by y = ab^x, where a represents the initial value, and b represents the rate

<h3>The equation of a city that has experienced a population growth</h3>

The initial population of the city is 10000, and the growth rate of the population is 4%.

So, the exponential equation is:

y = 10000 * 1.04^x

<h3>The equation of a city that has experienced a population decline</h3>

The initial population of the city is 12000, and the decay rate of the population is 3%.

So, the exponential equation is:

y = 12000* 0.97^x

<h3>The similarities in the equations</h3>

The similarity in both equations is that, they both represent exponential function.

<h3>The year the population of city A exceeds B</h3>

In (a) and (b), we have:

y = 10000 * 1.04^x ---- city A

y = 12000* 0.97^x --- city B

When city A exceeds city B, we have the following inequality

10000 * 1.04^x > 12000 * 0.97^x

Divide both sides by 10000

1.04^x > 1.2 * 0.97^x

Divide both sides by 0.97^x

(\frac{1.04}{0.97})^x > 1.2

1.07^x > 1.2

Take the natural logarithm of both sides

\ln(1.07)^x > \ln(1.2)

This gives

x\ln(1.07) > \ln(1.2)

Solve for x

x > \frac{\ln(1.2)}{\ln(1.07)}

x > 2.69

This means that, the population of city A will exceed city B after 3 years

<h3>The year the population of city A will be at least twice of city B</h3>

In (a) and (b), we have:

y = 10000 * 1.04^x ---- city A

y = 12000* 0.97^x --- city B

When city A is at least twice city B, we have the following inequality

10000 * 1.04^x \ge 2 * 12000 * 0.97^x

10000 * 1.04^x \ge 24000 * 0.97^x

Divide both sides by 10000

1.04^x \ge 2.4 * 0.97^x

Divide both sides by 0.97^x

(\frac{1.04}{ 0.97})^x \ge 2.4

1.07^x \ge 2.4

Take the natural logarithm of both sides

\ln(1.07)^x \ge \ln(2.4)

This gives

x\ln(1.07) \ge \ln(2.4)

Solve for x

x\ge \frac{\ln(2.4)}{\ln(1.07) }

x\ge 12.9

This means that, the population of city A will be at least twice city B after 13 years

Read more about exponential functions at:

brainly.com/question/11464095

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A bag contains 75 marbles some red some blue the ratio of red marbles to blue marbles is 3 to 2 how many red marbles are there
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The correct answer is 45
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Which is the completely factored form of the following equation?<br><br> 4a4b2−21a2b+5=0
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The completely factored equation is (a²b - 5)(4a²b - 1)

<h3>How to factor equation?</h3>

4a⁴b² - 21a²b + 5 = 0

let's expand the equation

Therefore,

4a⁴b² - 21a²b + 5 = 0

4a⁴b² - 20a²b  - a²b + 5 = 0

Rearrange the equation

4a⁴b² - a²b  - 20a²b + 5 = 0

Let's factorise the equation

4a⁴b² - a²b  - 20a²b + 5 = 0

a²b(4a²b - 1) - 5(4a²b - 1) = 0

Therefore, the completely factored equation is as follows:

a²b(4a²b - 1) - 5(4a²b - 1) = 0

(a²b - 5)(4a²b - 1)

learn more on equation here: brainly.com/question/8842252

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Its how much $$ they made minus the money they spent. The difference, or sum, is their profit
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Jaleh bought 17 bags of chicken feed for her chickens for the week. If Jaleh only 2/7 uses of the
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