Protocol. Like TCP/IP or HTTP etc
Answer:
log base 3a= -0.631.log a/3 base 3
Now, -log m= log 1/m
hence,
log base 3a= 0.631.log 3/a base 3
log base 3a/log 3/a base 3 =0.631
log base 3 ( a.3/a) =.631 since, log m/logn =log n(m)
log base 3 3=0.631
Hence, answer is log base 3 3=0.631
Explanation:
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I don’t understand that language
we translate the following statement given in terms of logarithms. 211 base x can be expressed into log 211 / log x while 152 base 8 can be expressed int o log 152 over log 8. In this case,
log 211 / log x = log 152 / log 8log x = 0.962x = 10^0.962 = 9.1632
