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vovangra [49]
3 years ago
13

Leo noticed that attackers have breached his wireless network. They seem to have used a brute-force attack on the WiFi protected

setup PIN to exploit the WAP and recover the WPA2 password. What type of attack is this?
Computers and Technology
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

It is called a WPS brutal force attack.

Explanation:

Wired and wireless networks are both susceptible to attacks. The wired network, the advantage as a cable connection, is more secure than wireless networks, but wireless network also have security measures like the wifi protected set up (WPS).

WPS is used to connect to a network without passphrase, but with a key combination or a PIN.

Brutal force attacks are used on WPS to forcefully generate the PIN, using a third party software.

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Zahra's softball team needs money for team T-shirts. The coach makes some fundraising suggestions, while team members brainstorm
user100 [1]

Answer:

I would think it would be D

Explanation:

that's basically what it said in the passage

5 0
3 years ago
Read 2 more answers
Douglas Engelbart is credited with the invention of _____
kicyunya [14]
He created computer mouse
6 0
3 years ago
Write a program, named sortlist, that reads three to four integers from the command line arguments and returns the sorted list o
yawa3891 [41]

Answer:

In C++:

void sortlist(char nums[],int charlent){    

   int Myarr[charlent];

const char s[4] = " ";  

char* tok;  

tok = strtok(nums, s);  

int i = 0;  

while (tok != 0) {  

 int y = atoi(tok);

 Myarr[i] = y;

 tok = strtok(0, s);  

 i++;

}  

int a;  

for (int i = 0; i < charlent; ++i) {

for (int j = i + 1; j < charlent; ++j) {

 if (Myarr[i] > Myarr[j]) {

  a =  Myarr[i];

  Myarr[i] = Myarr[j];

  Myarr[j] = a;

       }   }  }

 

for(int j = 0;j<charlent;j++){ printf(" %d",Myarr[j]); }  

}

Explanation:

This line defines the sortlist function. It receives chararray and its length as arguments

void sortlist(char nums[],int charlent){    

This declares an array

   int Myarr[len];

This declares a constant char s and also initializes it to space

const char s[4] = " ";  

This declares a token as a char pointer

char* tok;

This line gets the first token from the char

tok = strtok(nums, s);

This initializes variable i to 0

int i = 0;

The following while loop passes converts each token to integer and then passes the tokens to the array  

<em> while (tok != 0) {  </em>

<em>  int y = atoi(tok); </em><em>-> Convert token to integer</em><em> </em>

<em>  Myarr[i] = y; </em><em>-> Pass token to array</em><em> </em>

<em>  tok = strtok(0, s); </em><em>-> Read token</em><em> </em>

<em>  i++; </em>

<em> }  </em>

Next, is to sort the list.

int a;

This iterates through the list  

for (int i = 0; i < charlent; ++i) {

This iterates through every other elements of the list

for (int j = i + 1; j < charlent; ++j) {

This condition checks if the current element is greater than next element

 if (Myarr[i] > Myarr[j]) {

If true, swap both elements

<em>   a =  Myarr[i]; </em>

<em>   Myarr[i] = Myarr[j]; </em>

<em>   Myarr[j] = a; </em>

       }   }  }

The following iteration prints the sorted array

<em>for(int j = 0;j<charlent;j++){ printf(" %d",Myarr[j]); }  </em>

}

<em>See attachment for illustration of how to call the function from main</em>

Download cpp
7 0
3 years ago
Assume that two parallel arrays have been declared and initialized: healthOption an array of type char that contains letter code
eduard

/*

Since we have to check the first two options only as mentioned in last part of question the loop will work 2 times only and will compare the cost of first element and second and assign the healthoption accordingly

*/

for(int i =0;i<=1;i++){

if(annualCost[i]<annualCost[i+1]

best2 = healthOption[i]

else

best2 = healthOption[i+1]

}

6 0
3 years ago
Java Array question.
kodGreya [7K]

Answer:

3) 3 44 44

Explanation:

Given data

int [] val = { 3, 10, 44 };

The total number of parameters of given array are 3, so total length of array is also 3.

The indexing of array starts with '0', Therefore the <u>indexes</u> of array with length zero are: {0,1,2}

The value of array at index 0 is = 3

similarly

value at index 1 = 10

value at index 2 = 44

Here, Int i = 1 is storing the value '1' in integer variable i.

In addition to that, any value of index 'i' of an array is selected using array[i].

Therefore,

val[i] is selecting the value of array located at index '1' because i = 1.

val[i] = val[1] = 10

val[i+1] is selecting the value of array located at index 'i+1' that is (1+1) =2

val[i+1] = val[2] = 44

Finally,

val[i] = val[i + 1]; is copying the value placed at index 2 (44) to value placed at index 1 (10). Hence, the output would be {3 44 44}. So 3rd option is correct.

 

3 0
3 years ago
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