Answer:
Step-by-step explanation:
Which of the following is a typical cost associated with renting?
1 answer:
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Answer:
(1) y=C,
(2) x=C
(1) y=0
Step-by-step explanation:
For the linear equation, the power on the solitary variable must be 1.
When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.
When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.
(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant, , has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.
Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.
(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.
The solution for the equation is
x-C=0
, where
.
(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.
Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.
V1 - velocity first train
v2 - velocity second train
v2 > v1
v2 - v1 = 17 mph
We know, that:
![s_1+s_2=210 \ [miles] \\ \\ t_1=t_2=2h](https://tex.z-dn.net/?f=s_1%2Bs_2%3D210%20%5C%20%5Bmiles%5D%20%5C%5C%20%5C%5C%20t_1%3Dt_2%3D2h)
So:
NOw we've got simple system of equations:
![+\begin{cases} v_2-v_1=17 \\ v_2+v_1=105\end{cases} \\ \\ 2v_2=122 \qquad /:2 \\ \\ v_2=61 \qquad [mph] \\ \\ v_2-v_1=17 \\ \\ 61-v_1=17 \\ \\ v_1=44](https://tex.z-dn.net/?f=%2B%5Cbegin%7Bcases%7D%20v_2-v_1%3D17%20%5C%5C%20v_2%2Bv_1%3D105%5Cend%7Bcases%7D%20%5C%5C%20%5C%5C%202v_2%3D122%20%5Cqquad%20%2F%3A2%20%5C%5C%20%5C%5C%20v_2%3D61%20%5Cqquad%20%5Bmph%5D%20%5C%5C%20%5C%5C%20v_2-v_1%3D17%20%5C%5C%20%5C%5C%2061-v_1%3D17%20%5C%5C%20%5C%5C%20v_1%3D44)
Velocities of these trains are 61mph and 44mph
v2 - velocity second train
v2 > v1
v2 - v1 = 17 mph
We know, that:
So:
NOw we've got simple system of equations:
Velocities of these trains are 61mph and 44mph