Alex wrote the equation C= 2n describe a situation that this equation could represent

A calculator displays a result as 1.3540980 107 kg. the estimated uncertainty in the result is Â±2%. how many digits should be i

yan [13]

<span>2 significant digits.

Let's see what the range of possible values you can have for 1.3540980 if your uncertainty is +/- 2% 2% of 1.3540980 = 0.02 * 1.3540980 = 0.027082 So the lowest possible value for your result is 1.3540980 - 0.027082 = 1.327016 The largest possible result is 1.3540980 + 0.027082 = 1.38117996 Notice that only the 1st 2 digits of the result match which is reasonable since a 2% error means that your result is only accurate to within 1 part in 50.</span>

3 0

3 years ago

PLEASE HELP I HAVE 10 MINUTES LEFT

Lena [83]

Answer:

Manufacturers has to produce 63 DVD/Blu-Ray players to achieve a minimum cost of $644

Step-by-step explanation:

The cost equation is given as:

$C=0.04x^2-5x+800$

This is a quadratic equation in general form, which is:

$y=ax^2+bx+c$

Matching, we can say:

a = 0.04

b = -5

c = 800

The minimum occurs at $x=-\frac{b}{2a}$

and the minimum value would be to place that "x" value into the equation.

First, we find the minimum using values of a and b:

$x=-\frac{b}{2a}=-\frac{-5}{2(0.04)}=\frac{5}{0.08}=62.5$

Plugging this into original, we get:

$C=0.04x^2-5x+800\\C=0.04(62.5)^2-5(62.5)+800\\C=643.75$

Rounding off to nearest whole number, we can say:

Manufacturers has to produce 63 DVD/Blu-Ray players to achieve a minimum cost of $644

4 0

3 years ago

If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If $h(x)=\frac{f(x)}{g(x)}$ , then:

$h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}$

Since in our case we want the derivative of $h(x)$ at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is: