Correct answer: Option D- DNA ligase
Explanation: In option A, thymine is a nucleotide, so it is present throughout the replication process, wherever it is required. It is added to the newly formed DNA. In option B, Helicase enzyme is active during initiation and elongation stage, as it facilitates the opening of the winded DNA strands. Option C is nucleotidase and it has no role in DNA replication. So, the correct answer is DNA ligase, which is option D.
The okazaki fragments formed during DNA replication are sealed at the end. And in this step, DNA ligase is used. It catalyzes the formation of phosphodiester bond between the nucleotides of okazaki fragments. So it is the last active molecule of the process.
Polysaccharides have 1 sugar
disaccharides have 2 sugars
monosaccharides have a chain of sugars
Biochemical control and toxicity after intensity-modulated radiation therapy for prostate cancer. ... Biochemicalfailure was defined as PSA < post-treatment nadir+2.
It goes prophase, metaphase,anaphase,telophase. so the answer is C.
<span>strip-cropping:cultivation of crops in strips following the contours of the land</span>
