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irina1246 [14]
3 years ago
9

The scale from a playground to a scale drawing of the playground is 4 meters per centimeter.The length of the drawing of the pla

yground is 5.3 cm and the width is 3.8 cm. What is the area of the actual playground?
Mathematics
1 answer:
Scilla [17]3 years ago
6 0

Answer:

322.24 meters

Step-by-step explanation:

The scale is 4 meter per centimeter. Multiply 5.3 by 4 to get 21.2 meters. Multiply 5.3 by 4 to get 15.2 meters. Multiply 21.2 by 15.2 to get 322.24

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Solnce55 [7]

Answer:

4.75

Step-by-step explanation:

u×t=5 +1/2×-2×1/2²

7 0
3 years ago
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Which of the following are true?
Kitty [74]

Answer: c).

Both options are true. You can see that the whiskers of data set 2 (The lines extending on either side of the box plots) represent a much larger range of data than data set 1, and that the median in data set 2 (the line down the middle of the boxes) is greater than data set 1.

Hope this helps!

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3 years ago
What’s missing reason in the proof
svetlana [45]

Answer:

SSS congruence theorem.

Step-by-step explanation:

We have proved that the 3 sides of the triangles are congruent.

6 0
4 years ago
Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f
Reil [10]

Answer:

\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}

Step-by-step explanation:

The formula of a volume of a square pyramid:

V=\dfrac{1}{3}a^2h

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}

3 0
3 years ago
List five rational numbers between -4/5 and -2/3 . Please tell by step by step explaintion ​
attashe74 [19]

9514 1404 393

Answer:

  -0.67, -0.68, -0.69, -0.70, -0.71

Step-by-step explanation:

There are an infinite number of ways to do this.

Perhaps the simplest is to do it in decimal.

 -4/5 = -0.8

  -2/3 = -0.666... (repeating 6)

Any negative decimal number between these values will do. For example, ...

  -0.67, -0.68, -0.69, -0.70, -0.71

__

If you want to choose fractions that are evenly spaced between the given values, you can find their difference, then divide that difference into 6 parts (1 more than the number of numbers you need).

  -2/3 -(-4/5) = 4/5 -2/3 = (12 -10)/(5·3) = 2/15 . . . . length of interval

  1/6 of this difference is ...

     (1/6)(2/15) = 2/90 = 1/45

The interval end point nearest 0 is ...

  -2/3 = -30/45

so the 5 intermediate values will be that value with -1/45 repeatedly added:

  -31/45, -32/45, -33/45 = -11/15, -34/45, -35/45 = -7/9

_____

<em>Additional comment</em>

The fractions we came up with could be referred to as "5 arithmetic means between -2/3 and -4/5." There is nothing in the problem statement suggesting the values need to be evenly spaced.

When doing this in decimal, you can obtain a new value simply by adding more digits to the decimal fraction:

  -0.68, -0.685, -0.6853, -0.68531, -0.799

7 0
3 years ago
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