I think you should combine like terms
Answer:
C 64 students have half the height
Y-4=2/-3(x-6) I believe that’s the answer hope this helped
Answer:
1. 200 in.^2
2.
Step-by-step explanation:
1. Area of a trapezium=1/2(a+b)height
a=14 in.
b=20 in.+6 in. = 26 in.
height= ?
height can be gotten by using
formula : Soh Cah Toa
Toa is tangent∆= opposite/ adjacent
∆ = 60°
opp=? adj=6 in.
Tan 60° =opp/6 in.
Tan 60° = 1.732
1.732= opp/ 6 in.
opp=1.732*6 in.
opp = 10.392 approximately= 10 in.
Area of trapezium= 1/2*(14+26)*10(in.^2)
Area of trapezium= 1/2*40*10
= 1/2*400
= 200 in.^2 .
2. Area of triangle= 1/2* base* height
for first triangle =
base=4m
height =15m
Area: 1/2*4*15 ,1/2*60= 30m^2
second triangle =
base:?
height: 15m
using Pythagorean theorem;
hyp^2 = opposite ^2 + adjacent ^2
17^2 = 15^2 + adj^2
289= 225 + adj^2
adj^2 = 289-225= 64
square root
adj = 8m
area of second triangle : 1/2*8*15
: 1/2*120 :60m^2
total area: 30 m^2 +60m^2
==90 m^2
Answer: (C)2x + 8Y = 16
(0,2)
(8,0)
<span>Check the chart for a better understanding:
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