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NeX [460]
3 years ago
5

John won 72 pieces of gum

Mathematics
2 answers:
faust18 [17]3 years ago
8 0
18 Kids in his class you have to divide 72 by 4 which will give u 18
dusya [7]3 years ago
4 0

Answer:

Step-by-step explanation:

72 pcs gum - 4 remaining = 68 pcs of gum, 68 divided by 4

Divide 68 (amount of gumballs passed out to every student in Johns math class) by 4 (amount John gave to each student in his math class) = 17 Students in John math class Or 18 students when you include John.

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If you could help I would really appreciate it, but if not that’s fine. Thank you.
Kobotan [32]
Since 7 is greater than 5, you input it into the last equation.

2•(7) -7
14-7
7

The answer is 7!
3 0
3 years ago
Help me pls I really really need help with this I'm so bad at math
MAVERICK [17]
Question 7: Answer J (7/8 - 1/2 = 3/8)
6 0
4 years ago
Evaluate the expression: 231 - g for g = 17 .
nlexa [21]

Answer:

kuyky

Step-by-step explanation:

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6 0
3 years ago
Find the measures of the complementary angles that satisfy each case. One of the angles is 3 times larger than the other.
Nookie1986 [14]

Answer:

22.5° and 67.5°

Step-by-step explanation:

The sum of complementary angles equal 90°.

Given that one of the complementary angles is 3 times larger than the other, let "x" represent the other angle.

Thus, the following expression can be written to represent this case:

x + 3x = 90

Solve for x

4x = 90

Divide both sides by 4

\frac{4x}{4} = \frac{90}{4}

x = 22.5

The measure of the complementary angles are:

x = 22.5°

3x = 3(22.5) = 67.5°

6 0
3 years ago
Item 19 A cylindrical container of four rubber balls has a height of 20 centimeters and a diameter of 5 centimeters. Each ball i
Lady_Fox [76]
First you need to find the volume of the cylinder. Then find the volume of all 4 rubber balls (spheres). Subtract the cylinder's volume by the spheres' volumes.

Volume of cylinder: πr²h
                                   π2.5²(20) = 392.7 cm³

Volume of sphere: 4/3πr³
                                 4/3π2.5³ = 65.45 cm³

392.7 - 65.45 = 327.25

The amount of space in the container unoccupied by the rubber balls is 327 cm³.
7 0
4 years ago
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