∠ M ≅ ∠ R: true
<span>VL ≅ LT: true
</span><span>Δ MLV can be rotated about point L to map it to Δ RLT. : false
</span><span>A series of rigid transformations of Δ MLV maps it to Δ RLT. : true </span>
Answer:
The percentage of students who scored below 620 is 93.32%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Percentage of students who scored below 620:
This is the pvalue of Z when X = 620. So



has a pvalue of 0.9332
The percentage of students who scored below 620 is 93.32%.
Answer:
He walks the distance to his house from school twice, hope this helps!! (:
X=Distance
x*2