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marshall27 [118]
3 years ago
15

Pleeaaase hellllppppp…………………

Mathematics
2 answers:
Volgvan3 years ago
6 0

Answer:

C, 1/10 c^3d^4

Elena L [17]3 years ago
5 0

Remove the cubic root operation by raising all the terms by 1/3

1/100^1/3 c^9^1/3 a^12^1/3

Simplify:

1/10c^3a^4

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Write as a multiplication sentence. 5/6 divided by 1 1/2
avanturin [10]

Write as a multiplication sentence.

5/6 divided by 1 1/2

Remember that

1 1/2=1+1/2=3/2

so

\frac{5}{6}\colon\frac{3}{2}=\frac{5}{6}\cdot\frac{2}{3}

7 0
1 year ago
What is the slope of (-4,6) and (2,-5)
Dominik [7]

Answer:

-11/6

Step-by-step explanation:

Slope can be found with this equation:

(y₁ - y₂) / (x₁ - x₂)

What this essentially tells us to do is to put one set of the x and y coordinates into x₁ and y₁, respectfully. Then, put the other set of x and y points as x₂ and y₂.

With this scenerio, we can substitute the given points into the formula.

(6 - (-5)) / (-4 - 2) =

(6 + 5 ) / (-6) =

11 / (-6) =

-11/6

The slope is  - 11/6

4 0
3 years ago
Read 2 more answers
Write an inequality for the sentence. <br><br> c is not less than zero.
Zepler [3.9K]

c  \leqslant 0
6 0
3 years ago
Solve for h<br> Give an exact answer.<br> 3h=7( 2/7− 3/7 h)−10
romanna [79]
Its -4/3
Thank You.
Pls mark Brainliest!
6 0
3 years ago
13
il63 [147K]

The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify [\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2   and to find the value of s in x^s.

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}
Comparing with x^S
s = -16/3


Thus, the required value of the s = -16/3. None of these are correct.

Learn more about simplification here: brainly.com/question/12501526

#SPJ1

4 0
2 years ago
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