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snow_lady [41]
3 years ago
10

A town with a population of 5,000 grows 3% per year. Find the population at the end of two years using the Growth and Decay meth

od.
Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:

5304 people

Step-by-step explanation:

So, we have a population of 5000 people and it grows 3% per year. This problem wants us to find how much it will grow to at the end of 2 years.

With this, we have values that follow:

The formula: f(t) = a(1 + r)^t

a = 5000

r = 0.03

t = 2

Plugging it the values in the formula,

f(2) = 5000(1 + 0.03)^2

     = 5000(1.03)^2

     = 5304.5

Since there can't be a half person, we will have to reduce it down to 5304

f(2) = 5304

Let me know in the comments if you have any questions! If you could mark this answer as brainliest, I would very much appreciate it

jenyasd209 [6]3 years ago
6 0
The population would be 5300 at the end of two years because 3% of 5000 is 150 so 150x2=300. 5000+300=5300
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a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

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Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

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Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

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Total number of cases = 15

Required probability is \frac{8}{15}.

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4 years ago
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