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snow_lady [41]
3 years ago
10

A town with a population of 5,000 grows 3% per year. Find the population at the end of two years using the Growth and Decay meth

od.
Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:

5304 people

Step-by-step explanation:

So, we have a population of 5000 people and it grows 3% per year. This problem wants us to find how much it will grow to at the end of 2 years.

With this, we have values that follow:

The formula: f(t) = a(1 + r)^t

a = 5000

r = 0.03

t = 2

Plugging it the values in the formula,

f(2) = 5000(1 + 0.03)^2

     = 5000(1.03)^2

     = 5304.5

Since there can't be a half person, we will have to reduce it down to 5304

f(2) = 5304

Let me know in the comments if you have any questions! If you could mark this answer as brainliest, I would very much appreciate it

jenyasd209 [6]3 years ago
6 0
The population would be 5300 at the end of two years because 3% of 5000 is 150 so 150x2=300. 5000+300=5300
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Answer:

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Step-by-step explanation:

Given

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Solving (b):

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Answer:

1. y ≥ 100

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Step-by-step explanation:

Let y be the variable.

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If the discount (i.e y) is not less than 100, it means it is either 100 or greater than 100.

This can be written as:

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Answer:

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