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3 years ago

If AB = 15, BC = 12, and CA = 8, list the angles of angle abc in order from smallest to largest

Mathematics

1 answer:

Komok [63]3 years ago

7 0

Answer:

B= 32.11

A= 52.82

C= 95.07

Step-by-step explanation:

To find these angles, since you have all sides, you will need to use the law of cosines.

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Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes

$3^{2} x^{2} -12x+2^{2}$

now that $3^{2} x^{2}$ is ugly so it can be turned into $(3x)^{2}$

and -12x can be rewritten as $-2*3x*2$

so our equation now looks like $(3x)^2-2*3x*2+2^{2}$

There's a rule that says $a^{2} -2ab+b^{2} = (a-b)^{2}$

In our case, a=3x and b=2

so the final answer is

$(3x-2)^2$

5 0

2 years ago

For a field trip, the school bought 47 sandwiches for $4.60 each and 39 bags of chips for $1.25 each. How much did the school sp

NNADVOKAT [17]

Answer: $\$264.95$

Step-by-step explanation:

You know that 1 sandwich costs $4.60 and the school bought 47 sandwiches.

Therefore, in order to calculate the total cost of 47 sandwiches, you need to multiply this number of sandwiches bought by the schoole, by the cost of 1 sandwich. Then:

$sandwiches=(47)(\$4.60)\\\\sandwiches=\$216.2$

You know that 1 bag of chip costs $1.25 and the school bought 39 bags of chips.

So, in order to calculate the total cost of 39 bags of chips, you must multiply the total number of them bought by the school, by the cost of 1 bag of chips.

Then:

$bag\ of\ chips=(39)(\$1.25)\\\\bag\ of\ chips=\$48.75$

Therefore, the total amount school spent was:

$Total\ spent=\$216.2+\$48.75\\\\Total\ spent=\$264.95$

8 0

2 years ago

Read 2 more answers

T=3 and t=5 to determine if the expression 4(t+3) and 4 t+12 are equivalent

Mademuasel [1]

No they’re not equivalent because 4(t+12) =68 and 4t+12=32

7 0

2 years ago

A team of ten cyclists wants to choose leaders. in how many ways can the team choose one captain and then two assistants?

AURORKA [14]

Answer:

The team can look at who has been there the longest to pick the captian, and then the assistants can be two people who the captian would best work with. Also look for loyalty and integridy, honestly and good traits that have been shown.

4 0

3 years ago

Making coconut cookies. The recipe calls for 420 g of coconut and 120 g of sugar. Only has 252 g of coconut. How much sugar must

geniusboy [140]

Answer: 72 grams.

Step-by-step explanation:

Let be "s" the amount of sugar in grams that must be used for 252 grams of coconut to keep the same ratio of coconut to sugar.

Knowing that in the recipe for the coconut cookies, should be 420 grams of coconut and 120 grams of sugar, and you only have 252 grams of coconut, you can set up this proportion to find "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}$

Now, you need to solve for "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}\\\\s(\frac{420grams}{120grams})=252grams\\\\s=(252grams)(\frac{120grams}{420grams})\\\\s=72grams$

4 0

2 years ago