Ask question

Ask question

All categories

3 years ago

11

How many gallons equal 26 liters

1 answer:

Serjik [45]3 years ago

8 0

Answer:

6.8 gallions i believe. im not quite sure

You might be interested in

70% of the 100 students in the middle school bother lunch some of the students at bought their launch leave to attend an assembl

sukhopar [10]

42 students remain in the cafeteria

7 0

3 years ago

Prove each statement that is true and ﬁnd a counterexample for each statement that is false. Assume all sets are subsets of a un

tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

$A\cap (B-C)=(A\cap B)-(A\cap C)$

Proof:

Let x $\in A\cap (B-C)$

Then $x\in A$ and $x\in(B-C)$

When $x\in ( B-C)$ then $x\in B$ but $x\notin C$

Therefore, $x\in( A\cap B)$ but $x\notin (A\cap C)$

Hence, it is true.

Conversely , Let $x\in(A\cap B)$ but $x\notin(A\cap C)$

Then $x\in A$ and $x\in B$

When $x\notin ( A\cap C)$ then $x\notin C$

Therefor, $x\in A\cap (B-C)$

Hence, the statement is true.

5 0

3 years ago

Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from

Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that $P = 3000, r = 0.16, n = 1$

So

$A(t) = P(1 + \frac{r}{n})^{nt}$

$A(t) = 3000(1 + \frac{0.16}{1})^{t}$

$A(t) = 3000(1.16)^{t}$

(a) Find the amount in the account at the end of 1 year.

This is A(1).

$A(t) = 3000(1.16)^{t}$

$A(1) = 3000(1.16)^{1} = 3480$

(b) Find the amount in the account at the end of 2 years.

This is A(2).

$A(2) = 3000(1.16)^{2} = 4036.8$

4 0

3 years ago

Find the distance between the points given.

Maru [420]

Use the distance formula

$d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2$

Input corresponding numbers

$d = \sqrt {\left( {2- 6} \right)^2 + \left( {5-8} \right)^2$

Solve

$d = \sqrt {\left( {-4} \right)^2 + \left( {-3} \right)^2$

$\sqrt{16 + 9}$

$\sqrt{25} = 5\\\\ d=5$

So, the distance between the points given is 5

4 0

3 years ago

I can't figure out how to do this problem. Could somebody help me?

Verizon [17]

start by plugging in the value you already have, in this case, 5 for y.

-4x-3(5)=17

-4x-15=17

-4x=32

x=-8

however, since a is a+1, a would be 7 (making x 8)

also plz tell me if i read this wrong and it’s actually 1,5 rather than a+1 and 5 cause if i did i’m so sorry lol.

8 0

3 years ago