The amount that was invested 17 years ago is $2064.25.
The interest earned is $7935.75.
<h3>What is the amount invested 17 years ago?</h3>
The formula that would used to determine the amount that was invested 17 years ago is:
P = FV / (1 + r)^nm
Where:
- FV = Future value = 10,000
- P = Present value
- R = interest rate = 9.5 / 2 = 4.75%
- m = number of compounding = 2
- N = number of years = 17
10,000 / (1.0475)^(17 x 2) = $2064.25
Interest earned = 10,000 - 2064.25 = $7935.75
To learn more about future value, please check: brainly.com/question/18760477
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Answer:
A. Right angle traingle Is the answer
The rate is 0.30 km/min. The rate in linear functions, which must be assumed with only two given points can be traced to calculating the slope (m) of the line or rate.
m= (y2-y1) / (x2-x1)
with our two given points (x,y) we fill out the equation as:
M= (12 - 0) / (40 - 0) or M = 12/40 = 0.3
keeping our units intact 12 km / 40 min so the answer is 0.3 km/min
The answer would be C.
To find the density take Mass and divide by Volume
Mass
--------
Volume
82.0 g
---------
12.8 cm^<span>3
you get 6.4 g/cm^3</span>
