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Sholpan [36]
3 years ago
12

Find the next two terms in the sequence.

Mathematics
2 answers:
castortr0y [4]3 years ago
7 0
The first one subtracts 9.1 --> -26.6, -35.7
The second one subtracts 35 --> -105, -140
The third one subtracts 9.1 --> -44.8 , -53.9
The fourth one adds 9.1 --> 44.8 , 53.9
The fifth one adds 9.1 --> 37.1 , 46.2

I am sorry I do not have time to do the rest, but just find a pattern between the given terms and apply that to the next terms
Margaret [11]3 years ago
5 0
The first one is arithmetic with CD = -9.1  so the answer is B

Third  one is D

Second question:

a1 = 648 and r = 1/3  so 8th term  = 648 * (1/3)^7  =  8/27
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Kryger [21]

Answer:Can you Repeat the Problem Please?

6 0
3 years ago
700 is 10 times as much as blank
creativ13 [48]

700 is 10 times as much as 70 since 70 times 10 equals 700.

70 is the answer

Hope this helps!

8 0
2 years ago
Read 2 more answers
EPCIUCNO
cluponka [151]

Answer:

1 ⇒ D

2 ⇒ H

3 ⇒ B

4 ⇒ G

5 ⇒ A

6 ⇒ F

7 ⇒ E

8 ⇒ C

Step-by-step explanation:

* Lets explain how to solve the problem

- The left column has expressions and the right column has the

  equivalent expressions

- We must find the equivalent letter for each number

1.

# 7(12)

∵ 12 can be a sum of two numbers

∴ The equivalent expression to 7(12) is 7(8 + 4)

∴ 1 ⇒ D

2.

# 3(15)

∵ 3 can be a sum of two numbers

∴ The equivalent expression to 3(15) is (2 + 1)(15)

∴ 2 ⇒ H

3.

# 3a + 9

∵ 3 and 9 have a common factor 3

∵ 3a + 9 ⇒ divide them by 3

∵ 3a ÷ 3 = a and 9 ÷ 3 = 3

∴ 3a + 9 = 3(a + 3)

∴ The equivalent expression to 3a + 9 is 3(a + 3)

∴ 3 ⇒ B

4.

# 9a + 3

∵ 9 and 3 have a common factor 3

∵ 9a + 3 ⇒ divide them by 3

∵ 9a ÷ 3 = 3a and 3 ÷ 3 = 1

∴ 9a + 3 = 3(3a + 1)

∴ The equivalent expression to 9a + 3 is 3(3a + 1)

∴ 4 ⇒ G

5.

# 5 + 15a

∵ 5 and 15 have a common factor 5

∵ 5 + 15a ⇒ divide them by 5

∵ 5 ÷ 5 = 1 and 15a ÷ 5 = 3a

∴ 5 + 15a = 5(1 + 3a)

∴ The equivalent expression to 5 + 15a is 5(1 + 3a)

∴ 5 ⇒ A

6.

# 10 + 5a

∵ 10 and 5 have a common factor 5

∵ 10 + 5a ⇒ divide them by 5

∵ 10 ÷ 5 = 2 and 5a ÷ 5 = a

∴ 10 + 5a = 5(2 + aa)

∴ The equivalent expression to 10 + 5a is 5(2 + a)

∴ 6 ⇒ F

7.

# 3x + 6y + 9z

∵ The coefficient of x , y , z have a common factor 3

∵ 3x ÷ 3 = x

∵ 6y ÷ 3 = 2y

∵ 9z ÷ 3 = 3z

∴ 3x + 6y + 9z = 3(x + 2y + 3z)

∴ The equivalent expression to 3x + 6y + 9z is 3(x + 2y + 3z)

∴ 7 ⇒ E

8.

# 3x + 3y + 3z

∵ The coefficient of x , y , z have a common factor 3

∵ 3x ÷ 3 = x

∵ 3y ÷ 3 = y

∵ 3z ÷ 3 = z

∴ 3x + 3y + 3z = 3(x + y + z)

∴ The equivalent expression to 3x + 3y + 3z is 3(x + y + z)

∴ 8 ⇒ C

4 0
2 years ago
Hi I need help on my homework plz help ​
nordsb [41]
Okay I can help you !
8 0
2 years ago
5-12 divided by (6-2)-1<br><br> (4-3) multiply by 2+15 divided by (6-1)<br><br> Show your work
nataly862011 [7]

5-12 ÷(6-2)-1

Do whats in the parenthesis

5-12 ÷4-1

Do division next

5- 3- 1 = 1.

Do the same for the next.

(4-3) x 2+15 ÷(6-1)

1 x 2+15 ÷5

2+15÷5

2+3= 5

3 0
3 years ago
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