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Svetllana [295]
3 years ago
9

Analyze the diagram below and complete the instructions that follow.

Mathematics
1 answer:
Leokris [45]3 years ago
7 0
The answer is 8 percent
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Find the measure of an interior and an exterior angle of a regular 46-gon
trapecia [35]
For any polygon, the formula of the interior angle is 180 - 360/n where n is the number of sides of the polygon. The exterior angle is the supplementary angle of the interior angle. Hence when n is equal to 46, then interior angle is equal to 172.17 degrees and the exterior is equal to 7.83 degrees. 
7 0
3 years ago
Which shows one way to determine the factors of x^3 - 9x^2 + 5x - 45 by grouping ?
adoni [48]
You can group first two conjunctions and second two:
x^3 - 9x^2 + 5x - 45=(x^3-9x^2)+(5x-45).
In first brackets you have common x^2 and in second brackets common is 5:
(x^3-9x^2)+(5x-45)=x^2(x-9)+5(x-9)=(x-9)(x^2+5).
7 0
3 years ago
Do you know works at a dinner she earn six dollars each hour plus tips in one week she worked 37 hours a week and earned 43 tips
lukranit [14]

Answer:

265

Step-by-step explanation:

The computation of the amount that should be make out together is shown below:

Let us assume the number of hours be x

And, the total money earned be y

Now the equation would be

y = 6x  + 43

= 6(37) + 43

= 265

5 0
3 years ago
What is the approximate area of a circle with a radius of 13cm? A.40.8cm² B.530.7cm² C.784cm² D.2461.8cm²
Gnesinka [82]
It would be B (530.7) because if you do 3.14 x 13 x 13 (Or to the second power) Then you get 530.66, the round to the nearest tenths 
4 0
3 years ago
Read 2 more answers
In an experiment to determine whether there is a systematic difference between the weights obtained with two different mass bala
Maslowich

Answer:

H0: μd=0 Ha: μd≠0

t= 0.07607

On the basis of this we conclude that the mean weight differs between the two balances.

Step-by-step explanation:

The null and alternative hypotheses as

H0: μd=0 Ha: μd≠0

Significance level is set at ∝= 0.05

The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571

The test statistic under H0 is

t = d/ sd/ √n

Which has t distribution with n-1 degrees of freedom

Specimen        A               B           d = a - b         d²

1                     13.76        13.74         0.02           0.004

2                    12.47        12.45          0.02         0.004

3                    10.09        10.08           0.01        0.001

4                       8.91       8.92          -0.01          0.001

5                     13.57      13.54           0.03        0.009

<u>6                     12.74      12.75          -0.01        0.001</u>

<u>∑                                                      0.06         0.0173</u>

d`= ∑d/n= 0.006/6= 0.001

sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882

sd= 0.05368

t= 0.001/ 0.05368/ √6

t= 0.18629/2.449

t= 0.07607

Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.

3 0
3 years ago
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