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3 years ago

What does it mean when a line of best fit has a correlation coefficient close to 0?

Mathematics

1 answer:

Vinvika [58]3 years ago

7 0

It means the data is totally random havin no correlation at all

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Can someone help me with the question in the image. if correct i will mark as brainliest

Alex777 [14]

Answer:

$Multiply~the~length~of~the~leg~by~\sqrt{2}~to~arrive~at~the~length$ $of~the~hypotenuse = 6.$

Step-by-step explanation:

$To~find~the~length~of~the~ hypotenuse,~we~multiply~the~length~of~the~leg$ $by~\sqrt{2}:$

$3\sqrt{2} *\sqrt{2}=3*2=6$

$So~your~answer~to~this~question~is~option"b"$

$Hope~this~helps!$

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3 years ago

Write 6(9+2k)= -3 in written form

Alchen [17]

Answer:

27k+3=0

Step-by-step explanation:

Write in standard form.

this way?

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3 years ago

Please Help Me!<br> *Question Is Below Here*

SCORPION-xisa [38]

The product of this equation is 21 when the values of X and Y are imputed into the equation.

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3 years ago

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Walter used the iterative process to determine that 13 is between 3.61 and 3.62.

Rom4ik [11]

Answer: no both, 3.61^2 and 3.62^2 are greater than 13

Step-by-step explanation:

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3 years ago

Read 2 more answers

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

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3 years ago