What is the range? To find the range you take the biggest number subtracted by the smallest number. So 580-28=552 Range=552
What is the median? To find the median you order the numbers least to greatest and cross off the numbers left to right until you get the median aka middle number.
So the median is 130
What is the upper quartile? So the median was 130 so that is the middle quartile, and the numbers above that 187,192,228,301,580 are the upper numbers so find the middle two numbers of those numbers which is 228 and 301 so you add them and divide by 2 and get 264.5 which is the upper quartile
What is the mean? You add all the numbers up and divide by the number of numbers for the mean. So all numbers added up is 2056 then divide by the amount of numbers which is 12, so 2056/12 is 171.3
Hope this helped! Good luck! :)
Answer:
<em>x² + 4y²+ 2x - 24y + 33 = 0
</em>
<em />
<em>= (x+1)² + 4(y-3)² - 1 - 36 + 33 = 0
</em>
<em>= (x+1)² + 4(y-3)² = 4</em>
<em />
<em>= (x + 1)²/2² + (y - 3)²/1² = 1</em>
<em></em>
<em>This is an Ellipse: C(-1,3)</em>
<em>The Standard Form of an Equation of an Ellipse is : </em><em>(x - h)²/a²/ (y - k)²/b² = 1</em>
<em></em>
<em>where Pt(h,k) is the center. </em><em>(a variable positioned to correspond with major axis)</em>
<em>a and b are the respective vertices distances from center</em>
<em>and√a² - b²are the foci distances from center: a > b</em>
See attached picture for solution:
B.) Making Change
Hope this helps!!
There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960