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aliina [53]
3 years ago
13

Which operations is the following set closed under {...,-3,-2,1,3,...}

Mathematics
1 answer:
ch4aika [34]3 years ago
6 0
Addition should be the answer to your question
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Twenty to one meaning time​
Nadya [2.5K]

Answer: 20 minutes until 1 o'clock so it would be 12:40

Step-by-step explanation:

3 0
2 years ago
4 and 1 over 4 divided by 1 and 7 over 8
allsm [11]

Answer:

3 and 23 Over 32

Step-by-step explanation:

Done

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8 0
2 years ago
Find the zeros of the function. Enter the solutions from least to greatest . h(x) = (- 4x - 3)(x - 3) lesser x = greater
icang [17]

9514 1404 393

Answer:

  -3/4, 3

Step-by-step explanation:

The zeros are the values of x that make h(x)=0. Those are the values of x that make the factors of h(x) be zero.

  -4x -3 = 0   ⇒   x = -3/4

  x -3 = 0   ⇒   x = 3

The zeros of the function are -3/4 and 3.

3 0
3 years ago
The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}

A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}

Now, comparing areas:

\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

7 0
3 years ago
If an equation is an identity, then how many solutions does it have?
olga2289 [7]
Hello,

If an equation is an identity, then every value of the variable makes the egality true.

Generaly we resolve an equation in R.

In this case Sol=R
3 0
3 years ago
Read 2 more answers
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