Answer:
1 1/3 chocolate chips
Step-by-step explanation:
you have to divide 4 2/3 ÷ 3 1/2
change mixed number to improper fraction
14/3÷7/2
KFC-Keep Flip Change
14/3 × 2/7 = 28/21
28÷21= 1 1/3
Answer: Since her art and music sections each only had half the number of sheets of paper as a core subject, together the two sections had the same amount of paper as a core subject. Therefore, it is almost like her notebook had five core subjects, rather than four core subjects and two electives. If she divided the 200 sheets equally among the five core subjects, there would be 200 ÷ 5 = 40 sheets in each section. Now we can see that art would actually have half of this amount, or 20 sheets of paper.
Answer:
The inequality is ![c+2< 1](https://tex.z-dn.net/?f=c%2B2%3C%201)
Step-by-step explanation:
we know that
In the figure, the value of c is less than -1
so
![c< -1](https://tex.z-dn.net/?f=c%3C%20-1)
Adds both side +2
![c+2< -1+2](https://tex.z-dn.net/?f=c%2B2%3C%20-1%2B2)
![c+2< 1](https://tex.z-dn.net/?f=c%2B2%3C%201)
Answer:
1 3/5
Step-by-step explanation:
4/15÷1/6
Copy dot flip
4/15 * 6/1
24/15
Divide the top and bottom by 3
8/5
Change the improper fraction to a mixed number
5 goes into 8 1 time with 3 left over
1 3/5
Answer:
![3+ 2\mathbf{i}](https://tex.z-dn.net/?f=3%2B%202%5Cmathbf%7Bi%7D)
![3- 2\mathbf{i}](https://tex.z-dn.net/?f=3-%202%5Cmathbf%7Bi%7D)
Step-by-step explanation:
<u>Quadratic Equation Solving</u>
We have the equation:
![8x^2-48x=-104](https://tex.z-dn.net/?f=8x%5E2-48x%3D-104)
Divide by 8:
![x^2-6x=-13](https://tex.z-dn.net/?f=x%5E2-6x%3D-13)
Now complete the squares so the left side is a perfect square of a binomial:
![x^2-6x+9=-13+9=-4](https://tex.z-dn.net/?f=x%5E2-6x%2B9%3D-13%2B9%3D-4)
Factoring the perfect square:
![(x-3)^2=-4](https://tex.z-dn.net/?f=%28x-3%29%5E2%3D-4)
Taking the square root:
![x-3=\sqrt{-4}](https://tex.z-dn.net/?f=x-3%3D%5Csqrt%7B-4%7D)
The square root of a negative number is an imaginary number:
![x-3=\pm 2\mathbf{i}](https://tex.z-dn.net/?f=x-3%3D%5Cpm%202%5Cmathbf%7Bi%7D)
Solving for x:
![x=3\pm 2\mathbf{i}](https://tex.z-dn.net/?f=x%3D3%5Cpm%202%5Cmathbf%7Bi%7D)
The solutions are:
![3+ 2\mathbf{i}](https://tex.z-dn.net/?f=3%2B%202%5Cmathbf%7Bi%7D)
![3- 2\mathbf{i}](https://tex.z-dn.net/?f=3-%202%5Cmathbf%7Bi%7D)