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3 years ago

10

Danielle needs to walk 2.5 miles. If she wants to reach her destination in 30 minutes (1/2hour), how fast does she need to walk?

1 answer:

shepuryov [24]3 years ago

3 0

5 mph to get that answer you use the speed equation
speed(mph)=distance(in miles)/time(in hours)
2.5
------ = 5 mph
.5

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Find the slope of the line that is parallel to the line y=2x+5<br> <br> m=

OlgaM077 [116]

M=2
The slope intercept form is y=Mx+b,where m is the slope and b is the y intercept y=Mx+b

Using the slope intercept form the slope is 2 m=2

All lines that are parallel to y =2x-5 have the same slope of 2

M=2

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3 years ago

What fraction is equal to 3 1/9 ?

Masteriza [31]

Answer:

28/9

Step-by-step explanation:

We will have to convert the given question into improper fraction before solving

So let's solve the question

3 1/9

Can be written as 28/9 which is improper fraction

Since there's nothing that can be used to divide both the numerator and denominator

Then our final answer is 28/9

But in the case where the fraction can be divided we can actually solve further

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3 years ago

Read 2 more answers

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

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3 years ago

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Ann [662]

Answer:

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Step-by-step explanation:

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3 years ago

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Levart [38]

Answer:

X=-1/4

Step-by-step explanation:

<h2>8x=㏒₂/₅⁽²⁵/⁴⁾</h2>

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