Answer:
The 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Step-by-step explanation:
<u>Step :- (i)</u>
Given sample size 'n' =15
sample of the mean x⁻ = 33.2
The standard deviation of the sample 'S' = 8.3
<u>95% of confidence intervals</u>
<u></u>
<u></u>
<u>Step:-(ii)</u>
<u>The degrees of freedom γ=n-1 = 15-1=14</u>
The tabulated value t = 1.761 at 0.05 level of significance.
now substitute all possible values, we get
After calculation , we get
(33.2-3.7739 , 33.2+3.7739
(29.4261 ,36.9739)
<u>Conclusion</u>:-
the 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Answer:
she had $60 before she went for shopping
Step-by-step explanation:
PLZ MARK BRAINLIEST
Let x represent the amount of money that Victoria had before she went for shopping.
Victoria spent one-fourth or her birthday money on clothes. It means that the amount she spent on shopping is 1/4 × x = x/4. Amount that she was having left would be x - x/4 = 3x/4
She received another 25$ a week later. The amount that she is having at this point will be 3x/4 + 25
If she has a total of 70$ now, it means that
3x/4 + 25 = 70
Multiplying through by 4
3x + 100 = 280
3x ,= 280 - 100 = 180
x = 180/3 = 60
Answer: 37 + 19 = 56
Step-by-step explanation: easy all you need to do is take away nineteen from 56 then you get m
The difference is 105
3^2 - 2 + 7 =
(3 x 3) - 2 + 7 =
9 - 2 + 7 = 14
5^3 - 4^2 + 10 =
( 5 x 5 x 5) - ( 4 x 4) + 10
125 - 16 + 10 = 119
119 - 14 = 105
