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Inga [223]
3 years ago
15

If angles are supplementary, then one of the angles is an obtuse angle a. True b. False

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0
Attached the solution and work.

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Tom has $10 that he wants to use to buy pens and pencils. However, he does not want to buy more pens than pencils. A pen costs $
gregori [183]
Hello!

We 1st off, know that number of pencils = x

and that the number of pens = y

So now the Solving!:

3x + y = 10
x ≤ y

Draw the line 3x + y = 10 .[it passes by (0,10) and (-10/3,0)

Draw the line y=x [it passes by (0,0), (1,1), (2,2) etc]

Then the solution is the points with integer x and y, that belong to the segment of the line 3x +y = 10 between the x-axis and the line y=x. Those points are (1,7) , (2,4), (3, 1).


I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
7 0
3 years ago
Answer the folllowing sections on transversals
alukav5142 [94]

Answer:

A transversal is a line that intersects a system of lines. The transversal in this case, would be line a.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the evaluation 7w -14 for w = 9
borishaifa [10]
7(9)-14
63-14=51
Hope can help u
4 0
3 years ago
Read 2 more answers
HELPP I PUT MORE POINTS
PtichkaEL [24]

Answer:

TV = 48

Step-by-step explanation:

We can see that SW is twice the length of WV

42/21 = 2

We can find the length of TV this way

  • TU = 16 x 2
  • TU = 32
  • TV = 32 + 16
  • TV = 48

-Chetan K

7 0
3 years ago
How do you do <br> (x+y)(x-5y)+3(x+y)^2<br> ???? <br> Emergency, please help with full steps
Naddik [55]

Answer:

4 {x}^{2}  + 2xy - 2 {y}^{2}

Step-by-step explanation:

(x + y)(x - 5y) +  {3(x + y)}^{2}  \\ x(x - 5y) + y(x - 5y) + 3(x + y)(x + y) \\  {x}^{2}  - 5xy + xy - 5 {y}^{2}  + (3x + 3y)(x + y) \\  {x}^{2}  - 4xy - 5 {y}^{2}  + 3x(x + y) + 3y(x + y) \\  {x}^{2}  - 4xy - 5 {y}^{2}  + 3 {x}^{2}  + 3xy + 3xy + 3 {y}^{2}  \\  {x}^{2}  - 4xy - 5 {y}^{2}  + 3 {x}^{2}  + 6xy + 3 {y}^{2}  \\  {x}^{2}  + 3 {x}^{2}  - 4xy + 6xy - 5 {y}^{2}  + 3 {y}^{2}  \\ 4 {x}^{2}  + 2xy - 2 {y}^{2}

7 0
3 years ago
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