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schepotkina [342]
3 years ago
11

Write an equation of four lines that intersect to form the sides of a parallelogram

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0
The question requires that the four lines that intersect form a parallelogram but not an specific parallelogram, so you are not restricted by a diagram.

You can use these equations for the four lines:

1) y = 0 (it is the x-axis)

2) y = 4 (it is a line parallel to the x-axis, whose y-intercept is 4.

3) y = x (it is an inclined line that intersects both y = 0 and y = 4 lines.

4) y = x + 7 (it is a line parallel to y = x, that also intersect the both y = 0 and y = 4 lines.
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The volume is a rectangular prism is 7,200 cubic centimeters. It has a length of 24 centimeters and a width of 20 centimeters. W
Setler [38]
7,200 = (24)(20)h
15=h (just divide)
To check, 20*24*15 = 7,200 cubic centimeters so 15 cm is right
7 0
3 years ago
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Jose and Franco were playing a video game if Jose score 782,076 points and Franco scored 811,968 point what is the difference be
posledela

Answer:

29,892

Step-by-step explanation:

811,968-782,076

7 0
3 years ago
I don't remember how to solve this problem I missed yesterday when we learned it. 4(x-2+y)
kow [346]

Answer:

4x - 8 + 4y

Step-by-step explanation:

4(x - 2 + y)

4x - 8 + 4y

You multiply each term in the parenthesis by the number in front of it.

3 0
3 years ago
X – 81 = 1<br> X = ? <br> Pleaseee help me I’m strugglinggg
Firdavs [7]

Answer:

\huge{ \fbox{ \sf{82}}}

Step-by-step explanation:

\star{ \text{ \: x - 81 = 1}}

\text{Step \: 1 \:  : Move \: 81 \: to \: right \: hand \: side \: and \: change \: it's \: sign}

\hookrightarrow{ \sf{x = 1 + 81}}

\text{Step \: 2 \:  : Add \: the \: numbers : 1 \: and \: 81}

\hookrightarrow{ \sf{x = 82}}

The value of x is 82

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

6 0
3 years ago
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How do you simplify <img src="https://tex.z-dn.net/?f=7%5Csqrt%5B4%5D%7B80pq%5E%7B2%7Dr%5E%7B8%7D%20%20%7D" id="TexFormula1" tit
kondor19780726 [428]

Answer:

14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}

Step-by-step explanation:

The expression to simplify in this problem is

7\sqrt[4]{80pq^2r^8}

Which can be rewritten as

7(80pq^2r^8)^{\frac{1}{4}}

Or also as

7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot (q^2)^{\frac{1}{4}} \cdot (r^8)^{\frac{1}{4}}

Now we can apply the following rule for the calculation of the power of a power:

(a^m)^n = a^{m\cdot n}

So we get:

7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

Which can therefore be rewritten as

7\cdot (2^4\cdot 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

And so, we get

7\cdot 2 \cdot ( 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

which can be finally rewritten as

14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}

6 0
3 years ago
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